+1 vote
in Machine Kinematics by (38.0k points)
A 60 mm diameter shaft running in a bearing carries a load of 2000 N. If the coefficient of friction between the shaft and bearing is 0.03, find the power transmitted when it runs at 1440 r.p.m.

(a) 171.4 W

(b) 271.4 W

(c) 371.4 W

(d) 471.4 W

The question was posed to me in quiz.

This interesting question is from Laws of Fluid Friction in section Friction of Machine Kinematics

1 Answer

0 votes
by (106k points)
The correct answer is (b) 271.4 W

Easy explanation: Given : d = 60 mm or r = 30 mm = 0.03 m ; W = 2000 N ; μ = 0.03 ; N = 1440 r.p.m.

or ω = 2π × 1440/60 = 150.8 rad/s

We know that torque transmitted,

T = μ.W.r = 0.03 × 2000 × 0.03 = 1.8 N-m

∴ Power transmitted, P = T.ω = 1.8 × 150.8 = 271.4 W.

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