The correct answer is (b) 271.4 W
Easy explanation: Given : d = 60 mm or r = 30 mm = 0.03 m ; W = 2000 N ; μ = 0.03 ; N = 1440 r.p.m.
or ω = 2π × 1440/60 = 150.8 rad/s
We know that torque transmitted,
T = μ.W.r = 0.03 × 2000 × 0.03 = 1.8 N-m
∴ Power transmitted, P = T.ω = 1.8 × 150.8 = 271.4 W.