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The number of degrees of freedom of a planer linkage with 8 links and 9 simple revolute joints is

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+1 vote
in Machine Kinematics by (38.0k points)
The number of degrees of freedom of a planer linkage with 8 links and 9 simple revolute joints is

(a) 1

(b) 2

(c) 3

(d) 4

The question was asked in a job interview.

My query is from Inversion of Mechanism in division Simple Mechanisms of Machine Kinematics

1 Answer

0 votes
by (106k points)
Right answer is (c) 3

Best explanation: No. of links, I = 8

No. of revolute joints, J = 9

No. of higher pair, h = 0

Number of degree of freedom, n = 3(I -1) – 2j – h

                               = 3(8 – 1) – 2×9 – 0 = 3.

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