Question

During a discharge measured through a hydraulic spray nozzle was 450*10^-6m^3/min at nozzle operating pressure of 284 kPa. If the pressure is increased by 10%. The percent increase in discharge will be _______

(a) 4.9%

(b) 5.1%

(c) 3.6%

(d) 6.4%

The question was posed to me in final exam.

This intriguing question originated from Plant Protection Equipments topic in chapter Plant Protection Equipments of Farm Machinery

Answer 1

Correct option is (a) 4.9%

Best explanation: \(\frac{Q1}{Q2}=\Big\{\big(\frac{P1}{P2}\big)^{\frac{1}{2}}\Big\} \)

\(\frac{450*10^{-6}}{Q2} = \{\Big(\frac{284}{312.4}\Big)^{\frac{1}{2}}\} \)

Q2= 471.96*10^-6m^3/min

% increase = \(\frac{Q2-Q1}{Q1}\)*100 = \(\frac{(471.96-450)}{450} \)*100 = 4.9%