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A sprayer having 0.4 L/min nozzle discharge rate and 50 cm width of coverage is required to apply 0.8 kg of active ingredient per hectare. If 1 kg of active ingredient is content in 120 L of spray solution. What will be the speed of travel of sprayer?

(a) 2 km/h

(b) 5 km/h

(c) 3 km/h

(d) 4 km/h

The question was asked in a job interview.

This intriguing question originated from Plant Protection Equipments in chapter Plant Protection Equipments of Farm Machinery

1 Answer

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Best answer
The correct choice is (b) 5 km/h

To elaborate: NFR = 0.4 \(\frac{L}{min} \)

= 24 \(\frac{L}{h} \)

1 kg of spray ingredient is containing 120 L solution

0.8 will contain 120*0.8 L

Application rate = 96 \(\frac{L}{ha} \)

NFR = Application rate * S’ * S

24 = \(\frac{96*S’*0.5}{10} \)

S’ = \(\frac{24*10}{96*0.5} \)

S’ = 5 km/h

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