+1 vote
in Fluid Mechanics by (118k points)
If a gas X be confined inside a bulb as shown, by what percent will the pressure of the gas be higher or lower than the atmospheric pressure? (Take the atmospheric pressure equal to 101.3 kPa)

(a) 4:75% higher

(b) 4:75% lower

(c) 6:75% higher

(d) 6:75% lower

I had been asked this question in an international level competition.

Question is from Pressure Distribution in a Fluid in chapter Pressure and Its Measurement of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
The correct answer is (a) 4:75% higher

For explanation: Pa = Patm = 101.3

Pb = Pa + 0.9 * 9.81 * 0.03 = 101.56

Pc = Pb + 13.6 * 9.81 * 0.04 = 106.9

Pd = Pc – 1 * 9.81 * 0.05 = 106.41

Pe = Pd – 0.9 * 9.81 * 0.04 = 106.1

PX = Pe = 106.1

Since, PX > Patm, the percentage by which the pressure of the gas is higher than the atmospheric pressure will be

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