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A beaker is filled with a liquid of density ρ up to a height h. If half the liquid is replaced by equal volume of another liquid of twice the density, what will be the change in the base pressure?

(a) increased by ρgh

(b) decreased by ρgh

(c) increased by ρgh=2

(d) decreased by ρgh=2

I had been asked this question in an internship interview.

I need to ask this question from Pressure Distribution in a Fluid in division Pressure and Its Measurement of Fluid Mechanics

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Correct option is (c) increased by ρgh=2

The explanation is: Base pressure when the beaker is filled with a liquid of density ρ up to a height h = ρgh

Base pressure when half the liquid is replaced by equal volume of another liquid of twice the density

= ρg ^h⁄2 + 2ρg ^h⁄2 = ^3⁄2 ρgh

Thus the change in base pressure is = ρgh / 2.  Since, P2 > P1, there will be an increase in pressure.

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