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A beaker of height h is completely filled with water. Now two-third of the liquid is replaced by another liquid. If the pressure at the base of the beaker doubled, what is the specific gravity of the liquid poured?

(a) 0.5

(b) 1

(c) 2

(d) 2.5

I have been asked this question in an online interview.

This intriguing question originated from Pressure Distribution in a Fluid in division Pressure and Its Measurement of Fluid Mechanics

1 Answer

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Best answer
Correct answer is (d) 2.5

The explanation: Pressure at the base initially = Sw * ^h⁄3 * g; Pressure at the base after pouring the second liquid = Sw *  ^h⁄3 * g + Sl * ^2h⁄3 * g, where Sw and Sl are the specific gravities of water and the second liquid.

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