+1 vote
in Fluid Mechanics by (118k points)
A tank of height 3 m is completely filled with water. Now two-third of the liquid is taken out and an equal amount of two other immiscible liquids of specific gravities 0.8 and 1.2 are poured into the tank. By what percent will the pressure at the base of the tank change?

(a) 0%

(b) 5%higher

(c) 5%lower

(d) 10%higher

This question was posed to me during a job interview.

My question is from Pressure Distribution in a Fluid in chapter Pressure and Its Measurement of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Correct option is (a) 0%

Easy explanation: Pressure at the base initially = 1 * 9.81 * 3 = 29.43 kPa; Pressure at the base after adding the other two liquids= 0.8 * 9.81 * 1 + 1 * 9.81 * 1 + 1.2 * 9.81 * 1 kPa; Thus the pressure at the base remains the same.

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