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A beaker of height h is filled with a liquid of density ρ up to a certain limit. The beaker is rotated by an angle θ such that further increase in the angle will result in over flow of the liquid. If the liquid surface is exposed to the atmosphere, what will be the gauge pressure at point B?

(a) ρgh

(b) ρgh sin θ

(c) ρgh cos θ

(d) ρgh=2

I have been asked this question in an interview for job.

Asked question is from Pressure Distribution in a Fluid in section Pressure and Its Measurement of Fluid Mechanics

1 Answer

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Best answer
The correct option is (c) ρgh cos θ

To explain I would say: Vertical distance below the free surface at which the point B is located will be h cos θ.

Since the pressure at the free surface is atmospheric, the gauge pressure at B will be = 0 + ρgh cos θ.

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