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The below figure shows an inclined U-tube mercury manometer. The vertical end of the tube is exposed to a gas of gauge pressure 50 kPa and the inclined end is exposed to the atmosphere. The inclined part of the tube is at an angle of 30^o with the horizontal. Find the value of h (in cm) (take g = 9.8 m/s^2, ρmercury = 13600 kg/m^3)

(a) 60

(b) 50

(c) 75

(d) 25

I had been asked this question in my homework.

The above asked question is from Manometer topic in division Buoyancy and Floatation of Fluid Mechanics

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Correct choice is (c) 75

The explanation is: Pressure along the dotted line will be 50 kPa. Gauge pressure in an inclined manometer is given by P = ρ.g.h.sin (Ɵ). Substituting P, ρ and Ɵ, we get the value of h as 0.75 m.

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