In a U-tube mercury manometer, one end is exposed to the atmosphere and the other end is connected to a pressurized gas. The gauge pressure of the gas is found to be 40 kPa. Now, we change the manometric fluid to water. The height difference changes by: (ρmercury = 13600 kg/m^3, ρwater = 1000 kg/m^3).
(a) 1260%
(b) 92.64 %
(c) Remains unchanged (0%)
(d) 13.6%
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I need to ask this question from Manometer in chapter Buoyancy and Floatation of Fluid Mechanics