+1 vote
in Fluid Mechanics by (118k points)
A tank containing water upto a depth of 750 mm is moving vertically downward with a constant acceleration of 3.45 m/s^2. Find the force exerted by fluid of specific gravity .85 on the side of tank,width of tank is 2m

(a) 2682.75 N

(b) 5365.5 N

(c) 1341.25 N

(d) 4024.5 N

The question was asked during an online interview.

My question comes from Pressure Distribution in a Liquid in division Hydrostatic Forces on Surfaces of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Correct answer is (a) 2682.75 N

To explain I would say: p=ρ*g*h*(1-a/g)

                       =750*9.81*0.75*(1-3.45/9.81)

                       =3577 N/m^2

                      F=wAĥ

                        = 0.5*0.75*3984.5*2

                        = 2682.75 N.

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