+1 vote
in Fluid Mechanics by (118k points)
A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 4.5 m/s2.The length, width and depth of tank are 7 m, 3m, 2.5m respectively. If tank is open at the top then calculate the total force due to water acting on higher pressure end of the tank.

(a) 1.07 MN

(b) 2.14 MN

(c) 4.28 MN

(d) 4.35 MN

This question was posed to me in exam.

I would like to ask this question from Pressure Distribution in a Liquid in section Hydrostatic Forces on Surfaces of Fluid Mechanics

1 Answer

+1 vote
by (362k points)
selected by
 
Best answer
The correct choice is (a) 1.07 MN

To explain: tanθ=a/g

                     tanθ=4.5/9.8

                          θ=24.64⁰

h= d+(L/2)tanθ

  = 2.5+3.5tan24.64

  = 4.1 m

F=wAĥ

  =9810*2.68*4.1

  = 1.07 MN.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...