Question

A tank containing water upto a depth of 500 mm is moving vertically upward with a constant acceleration of 2.45 m/s^2. Find the force exerted by fluid of specific gravity .65 on the side of tank,width of tank is 1m.

(a) 996.1 N

(b) 1992.2 N

(c) 498.06 N

(d) 124.5 N

The question was posed to me in an internship interview.

I'd like to ask this question from Pressure Distribution in a Liquid topic in division Hydrostatic Forces on Surfaces of Fluid Mechanics

Answer 1

Right option is (a) 996.1 N

The best explanation: p=ρ*g*h*(1+a/g)

                       =650*9.81*0.5*(1+2.45/9.81)

                       =3984.5 N/m^2

                      F=wAĥ

                        = 650*9.81*0.5*0.5*3984.5

                        = 996.1N.