+1 vote
in Fluid Mechanics by (118k points)
A rectangular tank is moving horizontally in the direction of its length with a constant acceleration of 5.5 m/s^2. The length of tank is 5.5 m and depth is 2 m. If tank is open at the top then calculate the minimum pressure intensity at the bottom.

(a) 3.8 N/cm^2

(b) 1.9 N/cm^2

(c) 5.7 N/cm^2

(d) 2.6 N/cm^2

The question was posed to me during an interview.

This interesting question is from Pressure Distribution in a Liquid topic in division Hydrostatic Forces on Surfaces of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Right answer is (b) 1.9 N/cm^2

The best I can explain: tanθ=a/g

                     tanθ=5.5/9.8

                          θ=29.28⁰

h= d-(L/2)tanθ

  = 2-2.75 tan29.28

  = 3.21 m

p=ρ*g*h

  =1.9 N/cm^2.

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