+1 vote
in Fluid Mechanics by (118k points)
Find the density of metallic body which floats at the interface of mercury of sp.gr 13.6 and water such that 40 % of its volume is sub-merged in mercury and 60% in water.

(a) 6040 kg/m^3

(b) 12080 kg/m^3

(c) 24160 kg/m^3

(d) 3020 kg/m^3

I have been asked this question during an online exam.

I want to ask this question from Bouyancy topic in chapter Buoyancy and Floatation of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Right option is (a) 6040 kg/m^3

The explanation is: Total Bouyant force=Force of bouyancy due to water+Force of bouyancy due to mercury

                     For equilibrium, Total bouyant force= Weiht of body

        1000*9.81*0.6*V + 13.6*1000*9.81*0.4*V=ρ*g*V

         ρ=6040 kg/m^3.

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