Ask a Question

A diode match finder circuit has input voltage of 2.6v and output voltage is 5.78v. Calculate the voltage drop across diode 1N4735

← Prev Question Next Question →
+1 vote
in Linear Integrated Circuits by (37.1k points)
A diode match finder circuit has input voltage of 2.6v and output voltage is 5.78v. Calculate the voltage drop across diode 1N4735

(a) 2.22v

(b) 8.38v

(c) 3.18v

(d) 15.02v

I had been asked this question by my college director while I was bunking the class.

My question is based upon Voltage to Current Converter with Floating and Grounded Load in section Operational Amplifier Applications of Linear Integrated Circuits

1 Answer

0 votes
by (39.8k points)
Accurate answer is (c) 3.18v

Delve into insight with: The output voltage Vo =Vin+ VD.

∴ the voltage drop across 1N4735,  VD =Vo – Vin = 5.78-2.6 =3.18v.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community

Categories

Powered by TalkJarvis
...