+1 vote
in Linear Integrated Circuits by (37.1k points)
Determine the current through the diode, when the switch is in position 1, 2& 3. Assuming op-amps initially nulled.

(a) Io (LED) =4.01mA; Io (Zener) =4.01mA; Io (rectifier) =8.33mA

(b) Io (LED) =25mA; Io (Zener) =4.01mA; Io (rectifier) =4.01mA

(c) Io (LED) =16.67mA; Io (Zener) =16.66mA; Io (rectifier) =4.01mA

(d) Io (LED) =8.33mA; Io (Zener) =8.33mA; Io (rectifier) =8.33mA

The question was asked in an internship interview.

Question is from Voltage to Current Converter with Floating and Grounded Load topic in section Operational Amplifier Applications of Linear Integrated Circuits

1 Answer

0 votes
by (39.8k points)
The accurate choice is (d) Io (LED) =8.33mA; Io (Zener) =8.33mA; Io (rectifier) =8.33mA

Let me simplify it: All the diodes are connected one after another in the feedback path. Therefore, current through the diode remains same. Io =Vin/R1 =1.5/180 =8.33mA.

Related questions

We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community
...