Let the disturbing mass be 50 Kg, with radius of rotation = 0.1m, if one of the balancing mass is 30 Kg at a radius of rotation 0.1m then find the other balancing mass situated at a distance of 0.2m.

Question

Let the disturbing mass be 50 Kg, with radius of rotation = 0.1m, if one of the balancing mass is 30 Kg at a radius of rotation 0.1m then find the other balancing mass situated at a distance of 0.2m.

1 Answer

Related questions

+1 vote

1 answer

In a system two masses are used to balance the unbalanced forces. Find the mass of the balancing mass which has to be situated at a distance of 20cm, if the disturbing mass is of 100 Kg having radius of rotation of 0.1m. One of the balancing mass is 30 Kg with RoR of 10cm.

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

In the given figure, m1=20 Kg, m2=30Kg and m=50 Kg, if r1=0.2m and r=0.3m, l=1m, find l2.

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

In the given figure, m1=10, Kg m2=30Kg and m=50 Kg, if r1=0.2m and r=0.3m, l=1m, find l2.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Let the disturbing mass be 200 kg and the radius of rotation be 20 cm and the rotation speed be 50 rad/s, then calculate the centripetal force in kN.

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Let the disturbing mass be 100 kg and the radius of rotation be 10 cm and the rotation speed be 50 rad/s, then calculate the centrifugal force in kN.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Let the disturbing mass be 100 kg and the radius of rotation be 20 cm and the rotation speed be 50 rad/s, then calculate the centrifugal force in kN.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

In the given figure, m1=10 Kg, m2=30Kg and m=50 Kg, if r=0.3m, l=1m, find l2 = 0.5m, find r1 in m.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Let the centrifugal force in kN be 25 and the radius of rotation be 20 cm and the rotation speed be 50 rad/s, then calculate the mass defect in Kg.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin, if the angular acceleration of the rod is 23 000 rad/s^2, then find the correction couple in N-m.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A single mass defect needs to be balanced by a single balancing mass

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin. What will be the new radius of gyration?

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

If the rotation speed of the shaft increases then the balancing mass must also increase.

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Unbalanced mass leads to vibrations.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

Which of the following statement is correct? (a)In any engine, 100% of the reciprocating masses can be balanced dynamically

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A single cylinder oil engine works with a three rotor system, the shaft length is 2.5m and 70mm in diameter, the middle rotor is at a distance 1.5m from one end. Calculate the free torsional vibration frequency for a two node system in Hz if the mass moment of inertia of rotors in Kg-m^2 are: 0.15, 0.3 and 0.09. C=84 kN/mm^2

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A single cylinder oil engine works with a three rotor system, the shaft length is 2.5m and 70mm in diameter, the middle rotor is at a distance 1.5m from one end. Calculate the free torsional vibration frequency for a single node system in Hz if the mass moment of inertia of rotors in Kg-m^2 are: 0.15, 0.3 and 0.09. C=84 kN/mm^2

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

An aeroplane makes a complete half circle of 50 metres radius, towards left, when flying at 200 km per hr. The rotary engine and the propeller of the plane has a mass of 400 kg and a radius of gyration of 0.3 m. The engine rotates at 2400 r.p.m. clockwise when viewed from the rear. Find the gyroscopic couple on the aircraft.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A flywheel is mounted on a vertical shaft. The both ends of a shaft are fixed and its diameter is 50 mm. The flywheel has a mass of 500 kg, the modulus of rigidity for the shaft material is 80 GN/m^2 and its radius of gyration is 0.5 m. Find the natural frequency of torsional vibrations.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

In case of partial balancing of locomotives, the maximum magnitude of the unbalanced force perpendicular to the line of stroke is called hammer blow and this has to be limited by proper choice of the balancing mass and its radial position.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the power of the governor in N-m

asked Sep 23, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Neglecting friction at the sleeve, find the governor effort.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Neglecting friction at the sleeve, find the sleeve lift.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the governor effort.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

+1 vote

1 answer

A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Considering friction at the sleeve of 10N, find the range of speed in rpm.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

Fred · Answer 1 · 2022-10-15T02:08:01+0000

Correct answer is (d) 10

Best explanation: mr = m1mr + m2r2

50×0.1 = 30×0.1 + m2x0.2

5=3 + 0.2m

m2=10 Kg.

Let the disturbing mass be 50 Kg, with radius of rotation = 0.1m, if one of the balancing mass is 30 Kg at a radius of rotation 0.1m then find the other balancing mass situated at a distance of 0.2m.

Please log in or register to answer this question.

1 Answer

Please log in or register to add a comment.

Related questions

Categories