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A Porter governor has equal arms each of length 250 mm and pivoted on the axis of rotation. Each ball has a mass of 5 kg and the central load has a mass on the sleeve of 25 kg. The radius of rotation of the ball is 150 mm when the governor begins to lift and 200 mm when the governor is at maximum speed. Neglecting friction at the sleeve, find the power of the governor in N-m.

(a) 447

(b) 44.7

(c) 4.47

(d) 5.0

I had been asked this question in a national level competition.

I need to ask this question from Effort and Power of a Porter Governor in portion Governors of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
Right answer is (c) 4.47

The best explanation: We know that power of a governor is given by

effort of governor x sleeve lift

= 44.7 x 0.1 = 4.47 N-m.

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