+1 vote
in Machine Dynamics by (34.3k points)
The height of a Watt’s governor (in metres) in equal to

(a) 8.95/N^2

(b) 89.5/N^2

(c) 895/N^2

(d) 8950/N^2

The question was posed to me during an interview for a job.

My doubt is from Governors in portion Governors of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
Correct option is (c) 895/N^2

The explanation: Height of a Watt governor = g/ω^2

                                                           = 9.81/(2πN/60)^2

                                                           = 895/N^2

where N = Speed of the arm and ball about the spindle axis.

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