Ask a Question

The height of a Watt’s governor is equal to

← Prev Question Next Question →
+1 vote
in Machine Dynamics by (34.3k points)
The height of a Watt’s governor is equal to

(a) 8.95/N^2

(b) 89.5/N^2

(c) 895/N^2

(d) 8950/N^2

I got this question in examination.

My doubt stems from Types of Governors in portion Governors of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
Right option is (c) 895/N^2

To explain I would say: If N is the speed of the arm and ball about the spindle axis, then the height of the governor (h) is given by

h = 895/N^2 metres

Related questions

+1 vote
1 answer
The power of a governor is equal to
asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)
We welcome you to Carrieradda QnA with open heart. Our small community of enthusiastic learners are very helpful and supportive. Here on this platform you can ask questions and receive answers from other members of the community. We also monitor posted questions and answers periodically to maintain the quality and integrity of the platform. Hope you will join our beautiful community

Categories

Powered by TalkJarvis
...