Question

At equilibrium, the concentrations of N2=4.0 x10^-3M, O2 = 5.2 x 10^-3M and NO=3.9×10^-3M in a sealed vessel at 800K. What will be Kc for the reaction?

(a) 0.731

(b) 0.073

(c) 7.31

(d) 0.0007

The question was asked in a job interview.

This question is from Solid Liquid Equilibrium in chapter Contact Equilibrium Separation Process of Food Processing Unit Operations

Answer 1

The correct option is (a) 0.731

For explanation: For the reaction equilibrium constant, Kc can be written as,

Kc = [NO]^2/[N2][O2]

= (3.9 x 10^-3)^2/(4.0×10^-3M)(5.2×10^-3M)

= 0.731