+1 vote
in Mass Transfer by (37.1k points)
In an accident a container containing ethanol(s.g 0.789) falls down in a room of dimension 1*1*2(all in m). Ethanol forms a layer of 2mm. Ethanol vaporizes and diffuses through a stagnant film of air of thickness 2.5mm. What will be the time required for the water layer to disappear completely. The diffusivity of ethanol in air is 2.567*10^-5 m^2/s. the total pressure is 1.013 bar and the pressure of ethanol in bulk air is 0.02244 bar and at the ethanol-air interface is 0.02718bar. The temperature is 25.2°C.

(a) 4.73h

(b) 14.6h

(c) 5.87h

(d) 16.2h

The question was asked in exam.

My enquiry is from Diffusion in a Binary Gas Mixture topic in portion Diffusion in Solids and Molecular Diffusion in Fluids of Mass Transfer

1 Answer

0 votes
by (39.8k points)
The correct answer is (a) 4.73h

Explanation: This is the case of diffusion of through non diffusing B.

                NA=DP/RTZ*ln⁡[(P-P1)/(P-P2)]

                                     NA=(2.567*10-5*1.013)/(0.08317*298.2*2.5*10-3)*ln⁡[(1.013-0.02244)/(1.013-0.02718)] = 2.01*10^-6 kmol/m^2.s=9.259*10^-5kg/m^2.s

                                 Amount of ethanol = 2*10^-3*1=0.002m^3=1.578kg

                               Time for evaporation= 1.578/9.259*10^-5=17042.87s=4.73h.

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