Consider steady-state equimolar counterdiffusion through the converging-diverging tube. Given: r1=1cm; r2=2cm; NA=10^-6 kmol/m^2.s at the vessel 1 end of the tube. The rate of transport of B at the vessel 2 end of the tube is

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asked Sep 21, 2022 in Mass Transfer by Julian (37.1k points)

Consider steady-state equimolar counterdiffusion through the converging-diverging tube. Given: r1=1cm; r2=2cm; NA=10^-6 kmol/m^2.s at the vessel 1 end of the tube. The rate of transport of B at the vessel 2 end of the tube is

(a) 2*10^-6 kmol/s, towards vessel 1

(b) 2.5*^-7 kmol/s, towards vessel 1

(c) 5*10^-6 kmol/s, towards vessel 2

(d) 9*10^-7 kmol/s, towards vessel 2

The question was asked by my school teacher while I was bunking the class.

This interesting question is from Diffusion through Variable Area in chapter Diffusion in Solids and Molecular Diffusion in Fluids of Mass Transfer

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