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in Mass Transfer by (37.1k points)
In a binary gas mixture containing A and B, If NA=-2NB, what will be the expression for NA?

(a) 2(D*(P1-P2))/RTL

(b) (D*(P1-P2))/RTL

(c) DP*(2RTZ)^-1*ln[(P-P1)/(P-P2)].

(d) 2DP*(RTZ)^-1*ln⁡[(P-P1)/(P-P2)].

I got this question during an interview.

I would like to ask this question from Diffusion through Variable Area topic in section Diffusion in Solids and Molecular Diffusion in Fluids of Mass Transfer

1 Answer

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by (39.8k points)
The correct answer is (a) 2(D*(P1-P2))/RTL

To explain: NA= (NA+N)CA/C – DABdCA/dz

                        NA=(NA/2)PA/P – DAB(dPA/dz) /RT

                        NA(1-2PA/P) =  – DAB(dPA/dz)/RT

                        Integrate on both sides.

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