A reaction 3A+2B+C=1.5D+E occurs in a reactor at steady state. What will be the value of the flux ratio NA/ND

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A reaction 3A+2B+C=1.5D+E occurs in a reactor at steady state. What will be the value of the flux ratio NA/ND

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Chris · Answer 1 · 2022-10-11T12:27:30+0000

The correct answer is (a) -2

Best explanation: NA/ND= (rate of disappearance of A)/(rate of appearance of D)

= -3/1.5

= -2.

A reaction 3A+2B+C=1.5D+E occurs in a reactor at steady state. What will be the value of the flux ratio NA/ND

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