For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.

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For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.

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Chris · Answer 1 · 2022-10-12T14:53:23+0000

Right answer is (a) True

To explain I would say: For equimolar counter diffusion, the one component flux is negative of other.

For liquid molecular diffusion of A and B, steady state equimolar counter diffusion the N flux of A is negative of N flux of B.

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