The correct answer is (a) 4.9 kN/m^3
Easiest explanation: Given,
Discharge q=0.04 m^3/s
z=12m
Area A=50 m^2
coefficient of permeability k=1.6*10^-3m/s
the hydraulic gradient i is given by,
i=q/(kA)
i=0.04/(50*1.6*10^-3)
i=0.5
The seepage force per unit volume j is given by,
j=iγw
j=0.5*9.81
∴j=4.9 kN/m^3.