Correct answer is (d) 56.22 kN/m^2
To elaborate: Given,
Discharge q=0.04 m^3/s
z=12m
Area A=50 m^2
coefficient of permeability k=1.6*10^-3m/s
the hydraulic gradient i is given by,
i=q/(kA)
i=0.04/(50*1.6*10^-3)
i=0.5
∴ The effective pressure is given by
σ’=zγ’-izγw
σ’=12*9.59-0.5*12*9.81
σ’=56.22 kN/m^2.