Question

Determine the relationship between log-antilog method.

(a) lnVx×lnVy = ln(Vx+Vy)

(b) lnVx / lnVy = ln(Vx-Vy)

(c) lnVx -lnVy = ln(Vx/Vy)

(d) lnVx+ lnVy = ln(Vx×Vy)

This question was posed to me at a job interview.

My question is taken from Multiplier and Divider topic in portion Operational Amplifier Applications of Linear Integrated Circuits

Answer 1

Accurate answer is (d) lnVx+ lnVy = ln(Vx×Vy)

Here's an easy explanation: The log-anilog method relies on the mathematical relationship that is the sum of the logarithm of the product of those numbers.

=>   lnVx+lnVy = ln(Vx×Vy).