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Determine the transfer function for the practical differentiator

(a) Vo(s) /V1(s) = -S×RF×C1/(1+R1×C1)^2

(b) Vo(s) /V1(s) = -S×RF×C1/(1+RF×C1)^2

(c) Vo(s) /V1(s) = -S×RF×C1/(1+R1×CF)^2

(d) None of the mentioned

The question was asked by my college professor while I was bunking the class.

I want to ask this question from Differentiator in division Operational Amplifier Applications of Linear Integrated Circuits

1 Answer

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The transfer function for a practical differentiator is modified from the ideal case to include frequency compensation for stability. The correct answer is (a) Vo(s)/V1(s) = -S*RF*C1/(1+R1*C1)^2. This transfer function represents the practical differentiator where the frequency response includes the effect of both the feedback resistor RF and capacitor C1, as well as the input-limiting resistor R1. The denominator term (1+R1*C1)^2 provides the frequency-dependent compensation for practical op-amp differentiators.

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