Calculate the moment of inertia of an object having time period = 14 sec, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

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Calculate the moment of inertia of an object having time period = 14 sec, mass moment of inertia= 100 Kg-m^2 and the centre of gravity lies at a point 20 cm below the point of suspension.

asked Sep 23, 2022 in Machine Kinematics by Leo (38.0k points)

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Calculate the time period of an object having mass moment of inertia = 100 Kg-m^2, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

asked Sep 23, 2022 in Machine Kinematics by Leo (38.0k points)

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Calculate the frequency of vibration in Hz of an object having mass moment of inertia = 100 Kg-m^2, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

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If the mass moment inertia of the object is increased to 4 times then what will be the effect of time period of the simple pendulum?

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If the mass moment inertia of the object is increased to 4 times then what will be the effect of time period of the compound pendulum?

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If the mass of the object is doubled then what will be the effect of time period of the compound pendulum?

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A connecting rod of mass 5.5 kg is placed on a horizontal platform whose mass is 1.5 kg. It is suspended by three equal wires, each 1.25 m long, from a rigid support. The wires are equally spaced round the circumference of a circle of 125 mm radius. When the c.g. of the connecting rod coincides with the axis of the circle, the platform makes 10 angular oscillations in 30 seconds. Determine the mass moment of inertia about an axis through its c.g.

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An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. Find the mass located at gudgeon pin in Kg.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

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An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin. What will be the new radius of gyration?

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

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An Internal combustion engine has a connecting rod of mass 2 kg and the distance between the centre of crank and centre of gudgeon pin is 25 cm. The Center of Gravity lies at a point 10 cm from the gudgeon pin along the line of centres. The radius of gyration of this system about an axis through the Center of Gravity perpendicular to the plane of rotation is 11 cm. If two masses are used instead of the connecting rod, one at the gudgeon pin and other at the crank pin, if the angular acceleration of the rod is 23 000 rad/s^2, then find the correction couple in N-m.

asked Sep 22, 2022 in Machine Dynamics by Grayson (34.3k points)

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A small connecting rod of mass 1.5 kg is suspended in a horizontal plane by two wires 1.25 m long. The wires are attached to the rod at points 120 mm on either side of the centre of gravity. If the rod makes 20 oscillations in 40 seconds, find the radius of gyration of the rod about a vertical axis through the centre of gravity.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A body having moment of inertia of 30 kg m^2 is rotating at 210 RPM and mashes with another body at rest having M.I. of 40 kg m^2. The resultant speed after meshing will be

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The periodic time of a compound pendulum is …….. when the distance between the point of suspension and the center of gravity is equal to the radius of gyration of the body about its center of gravity.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A point moves with SIMPLE HARMONIC MOTION. When this point is 0.75 m away from the mid path, it has a velocity of 11 m/s and when 2 m from the centre of its path its velocity is 3 m/s. Find its time period in s.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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Which of the following apparatus is used to find the moment of inertia of an object?

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A particle executes linear simple harmonic motion with an amplitude of 2 cm. When the particle is at 1 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is

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When the body is suspended at the point of suspension, its periodic time and frequency will be _____________ as compared to the body suspended at the point of percussion.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (fn), respectively, are

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The equivalent length of simple pendulum depends upon the distance between the point of the suspension and the center of gravity.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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A helical spring, of negligible mass, and which is found to extend 0.25 mm under a mass of 1.5 kg, is made to support a mass of 60 kg. The spring and the mass system is displaced vertically through 12.5 mm and released. Find the velocity of the mass, when it is 5 mm below its rest position.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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All simple pendulums are compound pendulums.

asked Sep 24, 2022 in Machine Kinematics by Leo (38.0k points)

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