+1 vote
in Machine Kinematics by (38.0k points)
The centre of percussion is below the centre of gravity of the body and is at a distance equal to

(a) h / kG

(b) h.kG

(c) h^2/kG

(d) k^2G/h

The question was posed to me at a job interview.

I want to ask this question from Simple Harmonic Motion in section Simple Harmonic Motion of Machine Kinematics

1 Answer

0 votes
by (106k points)
Correct option is (d) k^2G/h

The explanation: The centre of oscillation is sometimes termed as centre of percussion. It is defined as that point at which a blow may be struck on a suspended body so that the reaction at the support is zero. The centre of percussion is below the centre of gravity and at a distance k^2G/h. The distance between the centre of suspension and the centre of percussion is equal to the equivalent length of a simple pendulum.

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