Right option is (a) 0.471 and 1.19 Hz
Explanation: Given k = 3.6 kN/m, c = 400 Ns/m, m = 50 kg
We know that, Natural Frequency
ωn = √k/m = 8.485 rad/ sec
And damping factor is given by,
d or ε = c/cc
= 0.471
Damping Natural frequency,
ωd = √1 – ε^2ωn
2πfd = √1 – ε^2ωn
fd = 1.19 Hz.