The Bifilar suspension method is used to determine

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A vehicle suspension system consists of a spring and a damper. The stiffness of the spring is 3.6 kN/m and the damping constant of the damper is 400 Ns/m. If the mass is 50 kg, then the damping factor (d ) and damped natural frequency (fn), respectively, are

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The strings used in bifilar suspension are perpendicular.

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To determine moment of inertia of a rigid object both bifilar and trifilar suspensions can be used.

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An automotive engine weighing 240 kg is supported on four springs with linear characteristics. Each of the front two springs have a stiffness of 16MN/m while the stiffness of each rear spring is 32MN/m. The engine speed (in rpm), at which resonance is likely to occur, is

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In S.H.M., acceleration is proportional to

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Polar moment of inertia(IP) of a circular disc is to be determined by suspending it by a wire and noting the frequency of oscillations(f)

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The frequency of oscillation of a bigger diameter cylinder compared to a small cylinder inside a cylinder concave surface will be

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The frequency of oscillation at moon compared to earth will be

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The frequency of oscillation of a cylinder inside a cylinder inside a cylindrical concave surface of bigger radius compared to a small radius will be

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In a bifilar suspension, if the length of the connecting rod is decreased, which of the following quantities will increase?

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The natural frequency of a spring-mass system on earth is ωn. The natural frequency of this system on the moon (gmoon =gearth/6) is

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A body having moment of inertia of 30 kg m^2 is rotating at 210 RPM and mashes with another body at rest having M.I. of 40 kg m^2. The resultant speed after meshing will be

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If the radius of gyration of a compound pendulum about an axis through c.g. is more, then its frequency of oscillation will be

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In S.H.M., the velocity vector w.r.t. displacement vector

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For an under damped harmonic oscillator, resonance

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Inertia force acts

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When the body is suspended at the point of suspension, its periodic time and frequency will be _____________ as compared to the body suspended at the point of percussion.

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The periodic time of a compound pendulum is …….. when the distance between the point of suspension and the center of gravity is equal to the radius of gyration of the body about its center of gravity.

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The distance between the center of suspension and center of percussion is equal to the equivalent length of a simple pendulum.

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Calculate the moment of inertia of an object having time period = 14 sec, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

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Calculate the frequency of vibration in Hz of an object having mass moment of inertia = 100 Kg-m^2, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

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The center of suspension and center of percussion are not interchangeable.

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The equivalent length of simple pendulum depends upon the distance between the point of the suspension and the center of gravity.

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Calculate the time period of an object having mass moment of inertia = 100 Kg-m^2, mass of 10 Kg and the centre of gravity lies at a point 20 cm below the point of suspension.

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Calculate the moment of inertia of an object having time period = 14 sec, mass moment of inertia= 100 Kg-m^2 and the centre of gravity lies at a point 20 cm below the point of suspension.

asked Sep 23, 2022 in Machine Kinematics by Leo (38.0k points)

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