+1 vote
in Machine Dynamics by (34.3k points)
In an NC machining operation, the tool has to be moved from point (5,4) to point (7,2) along a circular path with center at (5,2). Before starting the operation, the tool is at (5, 4). The correct G and M code for this motion is

(a) N010 G03 X7.0 Y2.0 I5.0 J2.0

(b) N010 G02 X7.0 Y2.0 I5.0 J2.0

(c) N010 G01 X7.0 Y2.0 I5.0 J2.0

(d) N010 G00 X7.0 Y2.0 I5.0 J2.0

The question was posed to me during an online interview.

My doubt is from Computer Aided Analysis for Four Bar Mechanism topic in chapter Computer Aided Analysis and Synthesis of Mechanisms of Machine Dynamics

1 Answer

0 votes
by (38.6k points)
The correct choice is (b) N010 G02 X7.0 Y2.0 I5.0 J2.0

Easiest explanation: G02 – Circular interpolation in clockwise direction

G91 – incremental dimens

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