Correct option is (a) \(dq=\frac{hγ_w}{4ηL}(R^2-r^2)2πrdr\)
Best explanation: Consider a capillary tube of length L and radius R.
dq=(2πrdr)v
substituting for velocity,
\(dq=(2πrdr)*\frac{hγ_w}{4ηL}(R^2-r^2)\)
\( ∴ dq=\frac{hγ_w}{4ηL}(R^2-r^2)2πrdr.\)