+2 votes
in Fluid Mechanics by (122k points)
Calculate the wetted perimeter of a triangular section having depth y and the side slope is Z.

I have been asked this question by my college professor while I was bunking the class.

Query is from Geometrical Properties of Triangular Section in division Flow in Open Channels of Fluid Mechanics

1 Answer

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by (13.9k points)
For a triangular section with depth y and side slope Z, the wetted perimeter can be calculated using the following formula:

Wetted Perimeter (P) = 2y(1 + Z2)^0.5

Where:

y = depth of the triangular section

Z = side slope (horizontal distance/vertical distance)

1 + Z2 is under the square root

Derivation:

In a triangular section, if the depth is y and the side slope is Z:

- The horizontal distance from the vertical centerline to the sloped side is Z × y

- The sloped side length = (y2 + (Zy)2)^0.5 = y(1 + Z2)^0.5

- Since there are two sloped sides, total sloped perimeter = 2y(1 + Z2)^0.5

- The bottom (wetted bed) is zero for an ideal triangular section

Therefore, the wetted perimeter of a triangular section = 2y(1 + Z2)^0.5

This formula is used in hydraulic calculations for open channel flow analysis.

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