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In the given figure the vertical angle is 60°, calculate the wetted area of the channel.

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+1 vote
in Fluid Mechanics by (118k points)
In the given figure the vertical angle is 60°, calculate the wetted area of the channel.

(a) 23.3m^2

(b) 33.3m^2

(c) 43.3m^2

(d) 53.3m^2

I had been asked this question in an online quiz.

My question is taken from Geometrical Properties of Triangular Section topic in section Flow in Open Channels of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Correct choice is (c) 43.3m^2

The best I can explain: Area = (5 tan⁡60°)(5)

Area = 43.3m^2.

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