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in Fluid Mechanics by (118k points)
A circular opening, 6m diameter, in a vertical side of a tank is closed by a disc of 6m diameter which can rotate about a horizontal diameter. Calculate the force on the disc. The centre of circular opening is at the depth of 5 m.

(a) 1.38 MN

(b) 2.76 MN

(c) 5.54 MN

(d) 7.85 MN

This question was addressed to me in an interview for job.

This interesting question is from Total Pressure & Vertical Plane Surface Submerged in a Liquid topic in portion Hydrostatic Forces on Surfaces of Fluid Mechanics

1 Answer

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Best answer
Correct choice is (a) 1.38 MN

Explanation: F=w*A*ŷ

                       =9.81*1000*3.142*3^2*5

                       =1.38 MN.

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