+1 vote
in Fluid Mechanics by (118k points)
The diameter of a pipe at the section 1 is 9 cm. If the velocity of water flowing through the pipe at section 1 is 4.8 m/s and section 2 is 9 m/s, Determine the area at section 2.

(a) 33.93 m^2

(b) 67.86 m^2

(c) 16.96 m^2

(d) 38.66 m^2

This question was addressed to me by my college professor while I was bunking the class.

This intriguing question originated from Continuity Equation in Two and Three Dimensions topic in division Kinematics of Flow and Ideal Flow of Fluid Mechanics

1 Answer

+1 vote
by (362k points)
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Best answer
The correct option is (a) 33.93 m^2

The best I can explain: According to continuity equation,

                         Area × velocity = constant

                         Area1*Velocity1 = Area2*Velocity2

                        (Area1*Velocity1)/Velocity2=Area2

                                       Area 2= 33.93 m^2.

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