+1 vote
in Fluid Mechanics by (118k points)
A liquid flows with the same velocity through two pipes 1 and 2 having the same diameter. If the length of the second pipe be twice that of the first pipe, what should be the ratio of the head loss in the two pipes?

(a) 1:2

(b) 2:1

(c) 1:4

(d) 4:1

I had been asked this question in an online interview.

This question is from Loss of Energy in Pipes topic in portion Flow Through Pipes of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
Correct answer is (a) 1:2

For explanation I would say: According to Darcy-Weisbach’s formula,

where hf is the head loss in the pipe, f is the co-efficient of friction, L is the length, D is the diameter and V is the flow velocity. Thus, hf1 : hf2 = L1 : L2 = 1 : 2.

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