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A liquid flows through pipes 1 and 2 with the same flow velocity. If the ratio of their pipe diameters d1 : d2 be 3:2, what will be the ratio of the head loss in the two pipes?

(a) 3:2

(b) 9:4

(c) 2:3

(d) 4:9

This question was posed to me by my college professor while I was bunking the class.

The question is from Loss of Energy in Pipes topic in portion Flow Through Pipes of Fluid Mechanics

1 Answer

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Best answer
The correct option is (c) 2:3

To elaborate: According to Darcy-Weisbach’s formula,

wherehf is the head loss in the pipe, f is the co-efficient of friction, L is the length, D is the diameter and V is the flow velocity. Thus, hf1 : hf2 = D2 : D1 = 2 : 3.

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