+1 vote
in Fluid Mechanics by (118k points)
A liquid flowss through two similar pipes 1 and 2. If the ratio of their flow velocities v1 : v2 be 2:3, what will be the ratio of the head loss in the two pipes?

(a) 3:2

(b) 9:4

(c) 2:3

(d) 4:9

This question was addressed to me in an online quiz.

My enquiry is from Loss of Energy in Pipes topic in division Flow Through Pipes of Fluid Mechanics

1 Answer

+2 votes
by (362k points)
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Best answer
The correct choice is (d) 4:9

Easy explanation: According to Darcy-Weisbach’s formula,

where hf is the head loss in the pipe, f is the co-efficient of friction, L is the length, D is the diameter and V is the flow velocity. Thus, hf1 : hf2 = v1 : v2  = 4 : 9.

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