Question

The velocity vector in a fluid is given V=5x^4+3y^2+2z( in metre/sec). What is the acceleration of it at point (1,3,4) ?

(a) 40 m/s^2

(b) 20 m/s^2

(c) 60 m/s^2

(d) 80 m/s^2

I got this question by my school principal while I was bunking the class.

I would like to ask this question from Velocity and Acceleration in division Kinematics of Flow and Ideal Flow of Fluid Mechanics

Answer 1

Right option is (a) 40 m/s^2

The best I can explain: By differentiating V=5x^42+2z, the acceleration obtained is V=20x^3+6y+2.

on putting the coordinates, the acceleration obtained is 40 m/s^2.