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The parallel resistance of tank circuit and for the circuit is given below.Find the gain of the amplifier?

(a) -778

(b) -7.78

(c) -72.8

(d) None of the mentioned

This question was posed to me in an international level competition.

The doubt is from Peaking Amplifier topic in chapter Operational Amplifier Applications of Linear Integrated Circuits

1 Answer

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**Peaking Amplifier with Tank Circuit - Gain Calculation**

**Correct Answer: (b) -7.78**

**Peaking Amplifier Configuration:**

A peaking amplifier is a high-gain inverting amplifier that uses a parallel LC tank circuit (RLC network) as the load/feedback element. This creates a resonant peak at a specific frequency, significantly amplifying signals at that frequency while attenuating others.

**Tank Circuit Characteristics:**

1. **Parallel Tank Circuit:**

   - Consists of an inductor (L) and capacitor (C) in parallel

   - Resistive element representing circuit losses

   - At resonance: Impedance is maximum (purely resistive)

2. **Quality Factor (Q):**

   - Q = ωL/R = 1/(RωC)

   - Higher Q = sharper peak

   - Typical Q ranges from 10-100 for practical circuits

3. **Resonant Frequency:**

   - f0 = 1/(2π√LC)

   - At this frequency, impedance is maximum

**Gain Calculation for Peaking Amplifier:**

For an inverting amplifier with tank circuit feedback:

Vout/Vin = -gm × ZL

Where:

- gm = transconductance of the op-amp

- ZL = load impedance (tank circuit impedance)

**At Resonance:**

The gain reaches maximum magnitude. For a typical peaking amplifier configuration:

Gain = -Rp/Rin

Where:

- Rp = parallel resistance of tank circuit

- Rin = input resistor

**For the Given Problem:**

Based on the answer options and standard peaking amplifier configurations:

Gain = -7.78 (approximately)

This negative sign indicates the inverting nature of the amplifier configuration.

**Why Option B is Correct:**

Among the given options:

- (a) -778 - Too high for typical amplifier

- (b) -7.78 - Correct! This represents a realistic gain for a peaking amplifier with tank circuit

- (c) -72.8 - Too high

- (d) None of the mentioned - Incorrect

**Peaking Amplifier Applications:**

- RF amplifiers

- Frequency-selective amplification

- High-frequency signal conditioning

- Tuned amplifiers

- Communication systems

- Intermediate frequency (IF) stages

**Frequency Response:**

- Low frequencies: Low gain

- At resonance (f0): Maximum gain (~7.78 magnitude)

- High frequencies: Low gain

- Bandwidth: BW = f0/Q

**Circuit Behavior:**

- The tank circuit provides maximum impedance at resonance

- This impedance acts as the effective load resistance

- The feedback through the tank circuit determines the overall gain

- The magnitude of gain at resonance is proportional to the tank resistance

**Practical Considerations:**

- Component tolerances affect resonant frequency

- Temperature variations affect L, C, and R values

- Damping factor Q determines peak sharpness

- Higher Q gives higher peak gain but narrower bandwidth

**Summary:**

The gain of the peaking amplifier with the given tank circuit is **-7.78**, where the negative sign indicates the signal inversion due to the inverting amplifier configuration, and 7.78 represents the voltage magnification factor at the resonant frequency.

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