Question

The band width of the peaking amplifier is expressed as

(a) BW = (fp× XL)/ (RF+Rp)

(b) BW =[ fp×(RF+Rp)× XL ] / (RF×Rp)

(c) BW =[ fp×(RF+Rp)] / (RF×Rp)

(d) BW = [fp×(RF+Rp) ]/ XL

The question was posed to me by my school principal while I was bunking the class.

My question is taken from Peaking Amplifier in portion Operational Amplifier Applications of Linear Integrated Circuits

Answer 1

Right option is (b) BW =[ fp×(RF+Rp)× XL ] / (RF×Rp)

Expand on the concept with: The bandwidth of the peaking amplifier,

BW = fp/Qp, where Qp – figure of merit of the parallel resonant circuit = (Rf||Rp)/Xl = (Rf×Rp)/[(Rf+Rp)× Xl]

=> BW = [fp×(Rf+Rp)× Xl] / (Rf×Rp).