+1 vote
in Linear Integrated Circuits by (39.8k points)
The expression for resonant frequency of the op-amp

(a) fp = 1/[2π×√(LC)].

(b) fp = (2π×√L)/C

(c) fp = 2π×√(LC)

(d) fp = 2π/√(LC)

The question was asked by my school teacher while I was bunking the class.

I'd like to ask this question from Peaking Amplifier topic in portion Operational Amplifier Applications of Linear Integrated Circuits

1 Answer

0 votes
by (6.5k points)

The correct answer is:

(a) fp=12πLCf_p = \frac{1}{2\pi \sqrt{LC}}

Explanation:

The expression for the resonant frequency fpf_p of a circuit, specifically for an LC circuit (inductor-capacitor), is given by:

fp=12πLCf_p = \frac{1}{2\pi \sqrt{LC}}

Where:

  • LL is the inductance in henries (H),
  • CC is the capacitance in farads (F),
  • fpf_p is the resonant frequency in hertz (Hz).

This formula applies to a series or parallel LC circuit, which is often used in peaking amplifiers to set the frequency response of the amplifier.

Why not the other options?

  • (b) fp=2πLCf_p = \frac{2\pi \sqrt{L}}{C}: This is incorrect as it doesn't follow the standard resonant frequency formula.
  • (c) fp=2πLCf_p = 2\pi \sqrt{LC}: This formula has the wrong dimensions and doesn't correspond to the correct resonant frequency formula.
  • (d) fp=2πLCf_p = \frac{2\pi}{\sqrt{LC}}: This is a misrepresentation of the formula; it incorrectly places the 2π2\pi factor.

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