+1 vote
in Mass Transfer by (37.1k points)
Guess the diameter of the bubble for an air-water system in a sparged vessel with gas holdup of 0.1 and liquid flow rate of 0.15 meters per second.

(a) 7.786 x10^-3

(b) 7.786 x10^-4

(c) 9.832 x10^-3

(d) 9.832 x10^-4

This question was posed to me during an interview.

This intriguing question originated from Gas-Liquid Equipments topic in division Equipment for Gas-Liquid Operations of Mass Transfer

1 Answer

0 votes
by (39.8k points)
The correct option is (a) 7.786 x10^-3

For explanation I would say: For a sparged vessel, the diameter of the bubble = (2.344 x10^-3)/(Relative velocity of the liquid upwards)^0.67

The relative velocity of the liquid upward= liquid flow rate/ (1- gas holdup)

Relative velocity = 0.15/0.9

Diameter = 7.786 x10^-3.

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